Question

How do you write the slope intercept form of the line `11x-8y=-48`?

Answer 1

`y=11/8x+6`

Explanation:

The equation of a line in `color(blue)"slope-intercept form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))`
where m represents the slope and b, the y-intercept.

`"Rearrange " 11x-8y=-48" into this form"`

subtract 11x from both sides of the equation.

`cancel(11x)cancel(-11x)-8y=-11x-48`

`rArr-8y=-11x-48`

divide all terms on both sides by - 8

`(cancel(-8) y)/cancel(-8)=(-11)/(-8)x-48/(-8)`

`rArry=11/8x+6larrcolor(red)" in slope-intercept form"`