Question

A model train with a mass of `8 kg` is moving along a track at `15 (cm)/s`. If the curvature of the track changes from a radius of `45 cm` to `225 cm`, by how much must the centripetal force applied by the tracks change?

Answer 1

The centripetal force is `0.1N`

Explanation:

The centripetal force is

`F=(mv^2)/r`

The variation in centripetal force is

`DeltaF=(mv^2)/(Delta r)`

`=(8*(0.15)^2)/(2.25-0.45)`

`=(8*0.0225)/1.8`

`=0.1N`