How do you write the standard form of the equation given (1,2) and slope 7?

1 Answer
Feb 12, 2017

#color(red)(7)x - color(blue)(1)y = color(green)(5)#

Explanation:

First, we can write the equation in point-slope form. The point-slope formula states: #(y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))#

Where #color(blue)(m)# is the slope and #color(red)(((x_1, y_1)))# is a point the line passes through.

Substituting the values from the problem gives:

#(y - color(red)(2)) = color(blue)(7)(x - color(red)(1))#

Now, we need to convert to standard form. The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

We convert as follows:

#y - color(red)(2) = (color(blue)(7) xx x) - (color(blue)(7) xxcolor(red)(1))#

#y - color(red)(2) = 7x - 7#

#-color(blue)(7x) + y - color(red)(2) + 2 = -color(blue)(7x) + 7x - 7 + 2#

#-7x + y - 0 = 0 - 5#

#-7x + y = -5#

#-1(-7x + y) = -1 xx -5#

#(-1 xx -7x) + (-1 xx y) = 5#

#color(red)(7)x - color(blue)(1)y = color(green)(5)#