Question

What is the angular momentum of a rod with a mass of `2 kg` and length of `7 m` that is spinning around its center at `5 Hz`?

Answer 1

The angular momentum is `=256.6kgm^2s^(-1)`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

For a rod , `I=(mL^2)/12`

So, `I=2*(7)^2/12=49/6kgm^2`

`omega=5*2pi=10pirads^-1`

`L=49/6*10pi=256.6kgm^2s^(-1)`