Question

If a spring has a constant of `10 (kg)/s^2`, how much work will it take to extend the spring by `40cm`?

Answer 1

I found: `0.8J`

Explanation:

The work needed to extend the spring will be equal to the final Elastic Potential Energy gained by the system because of the extension, i.e.:
`W=1/2kx^2=1/2*10*(0.4)^2=0.8J`