How do you solve the system of equations algebraically #3x+4y=-1, 6x-2y=3#?
1 Answer
Feb 14, 2017
#x=1/3#
#y=(-1)/2#
Explanation:
Given -
#3x+4y=-1# ------------------------(1)
#6x-2y=3# ------------------------(2)
#6x-2y=3# ------------------------(2)#(xx 2)#
#12x-4y=6# ------------------------(3)
#3x+4y=-1# -------------------------(1)
#12x-4y=6# ------------------------(3)#(1 + 3)#
#15x=5#
#x=5/15=1/3#
#x=1/3#
Substitute
#3(1/3)+4y=-1#
#1+4y=-1#
#4y=-1-1=-2#
#y=(-2)/4#
#y=(-1)/2#
