How do you solve #2/5sqrt(10x+6)=12#?

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Answer 1 · 2017-02-14T14:44:02

#x = 89.4#

#2/5sqrt(10x+6) = 12#

As with any equation, we need to isolate #x#.

Isolate the square root first.

#color(blue)(5/2 xx)2/5sqrt(10x+6) = color(blue)(5/2 xx)12#

#color(white)(............)sqrt(10x+6) = 30" "larr# now square both sides

#color(white)(..........)sqrt(10x+6)^2 = 30^2#

#color(white)(...............)10x+6 = 900" "larr# subtract 6 from both sides

#color(white)(......................)10x = 894#

#color(white)(.........................)x = 89.4#