Question #117c1

1 Answer
Matt
Feb 16, 2017

It would be less than that of air.

Explanation:

The wavelength of each harmonic is a function of the tube length so independent of the gas used. The speed of a wave is given by:

#c=flamda#

Since #lamda# for the harmonic is the same as air (independent of the gas), then since the speed (#c#), is lower in #CO_2#, the frequency (#f#) must also be lower for each harmonic.

Related questions
See all questions in Sound waves
Impact of this question
1841 views around the world
You can reuse this answer
Creative Commons License