A liquid of mass #54g# and density #2.164g*cm^-3# has WHAT volume?

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Answer 1 · 2017-02-18T10:39:03

#"Density, "rho# #=# #"mass"/"volume"#............

And thus #"Volume"="mass"/"density"="mass"/rho#

#=(54*cancelg)/(2.164*cancelg*cm^-3)~=25*1/(cm^-3)=25*cm^3#,

i.e. #1/a^-1=1/(1/a)=a#

A liquid of mass #54*g# and density #2.164*g*cm^-3# has WHAT volume?