Question

How do you multiply `(8x-11)(8x+11)`?

Answer 1

See the entire solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`(color(red)(8x) - color(red)(11))(color(blue)(8x) + color(blue)(11))` becomes:

`(color(red)(8x) xx color(blue)(8x)) + (color(red)(8x) xx color(blue)(11)) - (color(red)(11) xx color(blue)(8x)) - (color(red)(11) xx color(blue)(11))`

`64x^2 + 88x - 88x - 121`

We can now combine like terms:

`64x^2 + (88 - 88)x - 121`

`64x^2 + 0x - 121`

`64x^2 - 121`