How do you simplify the expression #(4x-3y)(x+5y)#?

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Answer 1 · 2017-02-19T19:24:39

See the entire simplification process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(4x) - color(red)(3y))(color(blue)(x) + color(blue)(5y))# becomes:

#(color(red)(4x) xx color(blue)(x)) + (color(red)(4x) xx color(blue)(5y)) - (color(red)(3y) xx color(blue)(x)) - (color(red)(3y) xx color(blue)(5y))#

#4x^2 + 20xy - 3xy - 15y^2#

We can now combine like terms:

#4x^2 + (20 - 3)xy - 15y^2#

#4x^2 + 17xy - 15y^2#