How do you solve: #3 >= 3x + 6#?

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Answer 1 · 2017-02-20T14:15:23

See the entire solution process below:

Step 1) Subtract #color(red)(6)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#3 - color(red)(6) >= 3x + 6 - color(red)(6)#

#-3 >= 3x + 0#

#-3 >= 3x#

Step 2) Divide each side of the inequality by #color(red)(3)# to solve for #x# while keeping the inequality balanced:

#-3/color(red)(3) >= (3x)/color(red)(3)#

#-1 >= (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#

#-1 >= x#

To solve in terms of #x# we must reverse or "flip" the inequality"

#x <= - 1#