Question

Question #848b4

Answer 1

The charge moved through the circuit is 4290`C`oulombs.

Explanation:

When there is a transfer of charge from one side of an area to the other, we say that there is an electric current through the area.
If a charge `'DeltaQ'` crosses an area in time `'Deltat'`, we define the average electric current through the area during the time as
`bari=(DeltaQ)/(Deltat)`.
Simply,
`i=Q/t or i=q//t`.
Here time taken by current to flow through the circuit as 13 minutes.
We have to change this seconds, because Ampere=Coulombs/seconds.
`:. t=780` `s`econds.

Substituting the numericals in the above equation we get,
`rArrq=i.t=5.5Axx780s=4290C`oulombs.