Question

A charge of `6 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `42 J` to `27 J`, what is the voltage between points A and B?

Answer 1

The voltage is `=2.5V`

Explanation:

Work is done by the electric charge in going from `A` to `B`

`DeltaW=q(V_B-V_A)`

`42-27=6*V_(AB)`

`V_(AB)=15/6=5/2=2.5V`