How do you find the slope that is perpendicular to the line #y=6x+1#?

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Answer 1 · 2017-02-22T13:13:51

See the entire explanation below:

This equation is in the slope intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Therefore the slope of the line for the equation in the problem is:

#color(red)(m = 6)#

A line perpendicular to the line in problem will have a slope (let's call it #m_p#) which is the negative inverse of the slope of this line. Or:

#m_p = -1/m#

Or, substituting the slope for the line in the problem gives:

#m_p = -1/6#