A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #4 m#. If the train's rate of revolution changes from #1/2 Hz# to #2/8 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1290 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-23T06:58:59

The centripetal force change by #=19.74N#

The centripetal force is

#F=mr omega^2#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=2*4*((1/2-1/4)2pi)^2#

#=8*4/16*pi^2=2pi^2#

#=19.74N#