Question

How do you find the discriminant, describe the number and type of root, and find the exact solution using the quadratic formula given `0.4x^2+x-0.3=0`?

Answer 1

`(-1+-sqrt1.48)/0.8`

Explanation:

Discriminant of the quadratic equation
`ax^2+bx+c=0`, in the quadratic formula is `sqrt(b^2-4ac)`.

In the present case a= 0.4, b= 1 and c= -0.3, hence the discriminant would be `sqrt(1-4(0.4)(-0.3) ) = sqrt 1.48`

Exact solution would be x= `(-1+- sqrt 1.48)/(2(0.4)`

=`(-1+-sqrt1.48)/0.8`