What is the Cartesian form of #(49,(-7pi)/4)#?

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Answer 1 · 2017-02-24T16:46:33

#(49,(-7pi)/4)# in Cartesian coordinates is #(49/sqrt2,49/sqrt2)# or #(34.65,34.65)#

Polar coordinates #(r,theta)# in Cartesian form is #(rcostheta,rsintheta)#

Hence, #(49,(-7pi)/4)# in Cartesian coordinates is

#(49cos((-7pi)/4),49sin((-7pi)/4))#

or #(49cos((-7pi)/4+2pi),49sin((-7pi)/4+2pi))#

or #(49cos(pi/4),49sin(pi/4))#

i.e. #(49xx1/sqrt2,49xx1/sqrt2)#

or #(49/sqrt2,49/sqrt2)#

i.e. #(34.65,34.65)#