A cylinder has inner and outer radii of #2 cm# and #18 cm#, respectively, and a mass of #2 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #15 Hz# to #16 Hz#, by how much does its angular momentum change?

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Answer 1 · 2017-02-25T06:42:08

The change in angular momentum is #=0.21kgm^2s^-1#

The angular momentum is #L=Iomega#

For a cylinder, #I=m(r_1^2+r_2^2)/2#

So, #I=2*(0.02^2+0.18^2)/2=0.0328kgm^2#

The change in angular momentum is

#DeltaL=IDelta omega#

#Delta omega=(16-15)*2pi=2pirads^-1#

#DeltaL=0.0328*2pi=0.21kgm^2s^-1#