A model train with a mass of #5 kg# is moving along a track at #14 (cm)/s#. If the curvature of the track changes from a radius of #88 cm# to #28 cm#, by how much must the centripetal force applied by the tracks change?

Question

1114 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-26T17:08:42

The change in centripetal force is #=0.239N#

The centripetal force is

#F=(mv^2)/r#

#m=mass=5kg#

#v=0.14ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=5*0.14^2/0.88=0.1114N#

#F_2=5*0.14^5/0.28=0.35N#

#DeltaF=0.35-0.1114=0.239N#