Question

Air has a density of 0.0013 g/mL. What is the mass of 6.0-L sample of air?

Answer 1

Approx. `8*mg`.

Explanation:

`rho,"density"="Mass"/"Volume"`.

And thus `"mass"` `=` `rhoxx"volume"`

`=0.0013*g*cancel(mL^-1)xx10^3*cancel(mL)*cancel(L^-1)xx6.0*cancelL`

`=7.8xx10^-3*g.`