Question

How do you balance `AgNO_3 +MgCl_2 → AgCl + Mg(NO_3)_2`?

Answer 1

`2"AgNO"_3 +"MgC"l_2 → 2"AgC"l + "Mg(NO"_3")"_2`

Explanation:

On the RHS, we have two nitrate ions. Therefore, we need `2` mols of `"AgNO"_3` to balance them. We now have two mols of `"Ag"^+` on the LHS but only one mol on the RHS. Thus we also need `2` mols `"AgC"l`.