A model train with a mass of #6 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #3 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 7, 2017

The change in centripetal force is #=2.304N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=6kg#

#v=0.12ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=6*0.12^2/0.03=2.88N#

#F_2=6*0.12^2/0.15=0.576N#

#DeltaF=2.88-0.576=2.304N#