What is the angular momentum of a rod with a mass of #2 kg# and length of #9 m# that is spinning around its center at #52 Hz#?

Question

1303 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-08T07:38:00

The angular momentum is #=4410.8kgm^2s^-1#

The angular momentum is #L=Iomega#

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*2*9^2= 27/2 kgm^2#

The angular velocity is

#omega=52*2pi=104pirads^-1#

The angular momentum is

#L=I omega=27/2*104pi=4410.8kgm^2s^-1#