How do you multiply #(3x - 5) ( 3x + 5)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer LM Mar 10, 2017 #9x^2-25# Explanation: #(a+b)(a-b) = a^2-b^2# substitute #a# with #3x# and #b# with #5#: #(3x+5)(3x-5) = (3x)^2 - 5^2# #=9x^2 - 25# #therefore (3x+5)(3x-5) = 9x^2 - 25# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 13090 views around the world You can reuse this answer Creative Commons License