A model train with a mass of #8 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #48 cm# to #240 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-11T09:31:10

The change in centripetal force is #=0.192N#

The centripetal force is

#F=(mv^2)/r#

#m=mass=8kg#

#v=0.12ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=8*0.12^2/0.48=0.24N#

#F_2=8*0.12^2/2.40=0.048N#

#DeltaF=0.24-0.048=0.192N#