How do you factor completely $y (y - 5) - 7 (y - 5)$ $y(y-5)-7(y-5)$ ?

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Answer 1 · 2017-03-12T23:57:50

$(y - 7) (y - 5)$ $(y-7)(y-5)$

Since what is inside the parenthesis matches, you take the other terms and put them together, and then multiply by what is inside the parenthesis.

Source: Example 1, Step 2/3: Factor by grouping

How do you factor completely y(y−5)−7(y−5)y(y-5)-7(y-5)?