Question #1c217

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Question #1c217

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Answer 1 · 2017-03-14T05:05:34

$n-butane$ $"n-butane"$ DOES NOT generate any geometric isomers.......

Explanation:

And nor does $isobutane$ $"isobutane"$ , $H_{3} {CCH(CH}_{3} {)CH}_{3}$ $"H"_3"CCH(CH"_3")CH"_3$ .

However, $2-butylene$ $"2-butylene"$ can generate cis and trans isomers as shown:

![galleryhip.com]( useruploads.socratic.org )

These are GEOMETRIC isomers, because the $C - C$ $C-C$ connectivity is IDENTICAL for each isomer: $C 1$ $C1$ connects to $C 2$ $C2$ .........to $C 4$ $C4$ . Their different geometry gives rise to different physical and chemical properties.

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Question #1c217

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