How do you multiply #(-4i)(-8-8i)(1-8i)#?
1 Answer
Mar 14, 2017
Explanation:
Distribute
#(8-8i)(1-8i)# using the FOIL method, say. Then multiply the result by#(-4i)#
#rArr(8-8i)(1-8i)#
#=8-64i-8i+64i^2#
#=-72i-56#
#rArr(-4i)(-72i-56)#
#=288i^2+224i#
#=224i-288#