Simplify #(x^2-x)/(x-1)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Andrew B. · Shwetank Mauria Mar 15, 2017 Yes. Good job! Explanation: #(x^2-x)/(x-1)# Factor out an #x# #=(x(x-1))/(x-1)# Cancel factors. #=(xcancel((x-1)))/cancel((x-1))=x# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 2021 views around the world You can reuse this answer Creative Commons License