How do you write a equation of a line through point (-6,4) and has a slope of -5/2?

1 Answer
Mar 15, 2017

#y=-5/2x-11#

Explanation:

The equation of a line in #color(blue)"point-slope form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and # (x_1,y_1)" a point on the line"#

#"here "m=-5/2" and " (x_1,y_1)=(-6,4)#

#rArry-4=-5/2(x-(-6))#

#rArry-4=-5/2(x+6)larrcolor(red)" in point-slope form"#

distributing the bracket and simplifying gives an alternative version of the equation.

#y-4=-5/2x-15#

#rArry=-5/2x-15+4#

#rArry=-5/2x-11larrcolor(red)" in slope-intercept form"#