Question

How do you solve `8( x + 11) > 32`?

Answer 1

`x> -7`

Explanation:

The first step is to distribute the bracket.

`rArr8x+88>32`

subtract 88 from both sides of the inequality.

`8xcancel(+88)cancel(-88)>32-88`

`rArr8x> -56`

divide both sides by 8

`(cancel(8) x)/cancel(8)=(-56)/8`

`rArrx> -7" is the solution"`

Answer 2

`x > -7`

Explanation:

`8(x+11)>32`

`8x+88>32`

`8x>32-88`

`8x > -56`

`(cancel(8)x)/cancel(8) > -(56)/8`

`x > -7`