How do you solve 7( 3s + 4) = 301?
3 Answers
Explanation:
First multiply out the brackets:
7xx3s+7xx4=301
21s+28=301
Next subtract
21s+28-28=301-28
21s=273
Next divide both sides by 21 and reduce:
(cancel21^color(red)(1)s)/(cancel21^color(red)1)=(cancel273^color(red)13)/(cancel21^color(red)1)
s=13
It is always a good idea (and very simple) to check your answer when you've finished.
Replace the constant with the value you found in the original formula. So in this case:
7(3xx13+4)=301
7(39+4)=301
7xx43=301
301=301
The left hand side (LHS) and right hand side (RHS) of the equal's match, proving the answer correct.
Explanation:
The first step is to distribute the bracket on the left side.
rArr21s+28=301 subtract 28 from both sides.
21scancel(+28)cancel(-28)=301-28
rArr21s=273 divide both sides by 21
(cancel(21) s)/cancel(21)=273/21
rArrs=13" is the solution"
Just another approach!
Explanation:
The objective is to work you way to getting just 1 of s and for it to be on its own on one side of the = and everything else on the other side.
Isolating the
Isolating 3s: subtract 4 from both sides
Final isolation step: divide both sides by 3
But