How do you solve 7( 3s + 4) = 301?

3 Answers
Mar 16, 2017

s=13

Explanation:

7(3s+4)=301

First multiply out the brackets:

7xx3s+7xx4=301

21s+28=301

Next subtract 28 from both sides of the = sign:

21s+28-28=301-28

21s=273

Next divide both sides by 21 and reduce:

(cancel21^color(red)(1)s)/(cancel21^color(red)1)=(cancel273^color(red)13)/(cancel21^color(red)1)

s=13

It is always a good idea (and very simple) to check your answer when you've finished.

Replace the constant with the value you found in the original formula. So in this case:

7(3xx13+4)=301

7(39+4)=301

7xx43=301

301=301

The left hand side (LHS) and right hand side (RHS) of the equal's match, proving the answer correct.

Mar 16, 2017

s=13

Explanation:

The first step is to distribute the bracket on the left side.

rArr21s+28=301

subtract 28 from both sides.

21scancel(+28)cancel(-28)=301-28

rArr21s=273

divide both sides by 21

(cancel(21) s)/cancel(21)=273/21

rArrs=13" is the solution"

Mar 16, 2017

Just another approach!

s=13

Explanation:

The objective is to work you way to getting just 1 of s and for it to be on its own on one side of the = and everything else on the other side.

Isolating the ul("'group'") of values that has s in it- divide both sides by 7

3s+4=301/7

Isolating 3s: subtract 4 from both sides

3s=301/7-4

Final isolation step: divide both sides by 3

s=301/(3xx7)-4/3

s=301/21-4/3

But 3xx7=21

color(green)(s=301/21-[4/3color(red)(xx1) ])

color(green)(s=301/21-[4/3color(red)(xx7/7) ])

s=301/21-28/21

s=273/21 = 13