Question

How do you calculate the pressure in atmospheres of 1.00 mol of argon in a .500-L container at 29.0°C?

Answer 1

`P~=50*atm`

Explanation:

We use the Ideal Gas Equation.........`P=(nRT)/V`

`(1.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx302*cancelK)/(0.500*cancelL)=??*atm`