Question

How do you find the exact value of `cosxsinx+sinx=0` in the interval `0<=x<360`?

Answer 1

`{0^@, 180^@}`

Explanation:

We can factor out a sine.

`sinx(cosx + 1) = 0`

We now have two possible cases.

Case 1: `sinx = 0`

`x = 0^@, 180^@`

Case 2: `cosx + 1 = 0`

`cosx = -1`

`x = 180^@`

`:.`Our solution set in `0 <= x < 360` is `{0^@, 180^@}`.

Hopefully this helps!