A cylinder has inner and outer radii of $4 cm$ and $7 cm$ , respectively, and a mass of $6 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $15 Hz$ to $11 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-03-20T13:37:29

The change in angular momentum is $=0.49kgm^2s^-1$

The angular momentum is $L=Iomega$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=6*((0.04^2+0.07^2))/2=0.0195kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(15-11)*2pi=(8pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0195*8pi=0.49kgm^2s^-1$

A cylinder has inner and outer radii of 4 cm4 cm and 7 cm7 cm, respectively, and a mass of 6 kg6 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 15 Hz15 Hz to 11 Hz11 Hz, by how much does its angular momentum change?