Question

Suppose a balloon containing 1.30 L of air at 24.7°C is placed into a beaker.containing liquid nitrogen at -78.5°C. What will the volume of the sample of air become (at constant pressure)?

Answer 1

Use Charles law

Explanation:

`V_1/T_1 = V_2/T_2`

Where V = volume
T = temperature

`V_1 = 1.3L`

`T_1 = 24.7^oC`

`T_2 = -78.5^oC`

Convert these units to the appropriate units if required

`24.7^oC = 24.7^oC + 273.15K = 297.85K`

`-78.5^oC + 273.15K = 194.65K`

Plug in the variables

`(1.3L)/(297.85K) = (V_1)/(194.65K)`

`0.00436 = (V_1)/(194.65K)`

`V_1 = 0.00436 * 194.65K`

= 0.848674L (The balloon will shrink very much)