Question

What is the standard form of a polynomial `(2y-8)(y-4)`?

Answer 1

See the entire solution process below:

Explanation:

We need to multiply these two terms to put the expression in the standard form of a polynomial. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`(color(red)(2y) - color(red)(8))(color(blue)(y) - color(blue)(4))` becomes:

`(color(red)(2y) xx color(blue)(y)) - (color(red)(2y) xx color(blue)(4)) - (color(red)(8) xx color(blue)(y)) + (color(red)(8) xx color(blue)(4))`

`2y^2 - 8y - 8y + 32`

We can now combine like terms:

`2y^2 + (-8 - 8)y + 32`

`2y^2 - 16y + 32`