What is the the vertex of #y = (x + 2)^2 + 3x+4 #?

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Answer 1 · 2017-03-22T21:04:39

#"Vertex{-3.5" , "-4.25}#

#y=(x+2)^2+3x+4#

#y=x^2+4x+4+3x+4#

#y=x^2+7x+8" (1)"#

#(d y)/(d x)=0#

#(d y)/(d x)=2x+7=0#

#2x+7=0#

#2x=-7#

#x=-7/2=-3.5#

#"use (1)"#

#y=(-7/2)^2-7(7/2)+8#

#y=49/4-49/2+8#

#y=(49-98+32)/4#

#y=-17/4=-4.25#

#"Vertex{-3.5" , "-4.25}#