A model train, with a mass of #5 kg#, is moving on a circular track with a radius of #3 m#. If the train's rate of revolution changes from #1/4 Hz# to #3/8 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1361 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-23T13:16:39

The centripetal force change by #=9.52N#

The centripetal force is

#F=mr omega^2#

mass is #m=5kg#

radius #r=3m#

#Delta omega=(3/8-1/4)*2pi=(1/4pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=5*3*(1/4pi)^2#

#=9.25N#