A model train with a mass of #6 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #3 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

Question

1221 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-26T10:14:40

The change in centripetal force is #=3.6N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=6kg#

speed, #v=0.15ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=6*0.15^2/0.03=4.5N#

#F_2=6*0.15^2/0.15=0.9N#

#DeltaF=4.5-0.9=3.6N#