Question

An object with a mass of `6 kg` is revolving around a point at a distance of `8 m`. If the object is making revolutions at a frequency of `4 Hz`, what is the centripetal force acting on the object?

Answer 1

The centripetal force is `=30319.4N`

Explanation:

The centripetal force acting on an object is

`F=mr omega^2`

The mass, `m=6kg`

The radius, `r=8m`

The angularvelocity is

`omega=4*2pi=8pi`

So

The centripetal force is

`F=6*8*(8pi)^2=30319.4N`