How do you factor #4t^3=36t#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Barney V. Mar 31, 2017 #t=3# and #t=-3# Explanation: #4t^3=36t# #:.4t^3-36t=0# #:.4t(t^2-9)=0# #:.4t(t^2-3^2)=0# #:.4t(t-3)(t+3)=0# #:.t-3=0,t+3=0# #:.t=3# and #t=-3# substitute t=3# #:.4(3)^3=36(3)# #:.4*27=36*3# #:.108=108# substitute t=-3# #:.4(-3)^3=36(-3)# #:.4(-27)=-108# #:.-108=-108# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1307 views around the world You can reuse this answer Creative Commons License