How do you factor #4x^3-2x^2+6x-3#?

1 Answer
NickTheTurtle
Apr 2, 2017

#(2x-1)(2x^2+3)#

Explanation:

First, we group the terms like this: #(4x^3-2x^2)+(6x-3)#. We can factor these groups individually: #2x^2(2x-1)+3(2x-1)#.

Notice that there is a common factor: #(2x-1)#. We can factor this out again: #(2x-1)(2x^2+3)#. Now, we can't really factor this further. So, our answer is #(2x-1)(2x^2+3)#.

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