Question

How do you find the zeros, real and imaginary, of `y= -7x^2-5x+23` using the quadratic formula?

Answer 1

`x = (-5 +- 25.87)/14`

Explanation:

y = - 7x^2 - 5x + 23 = 0
Use the improved quadratic formula (Socratic Search).
D = d^2 = b^2 - 4ac = 25 + 644 = 669 --> d = +- 25.87
There are 2 real roots:
`x = - b/(2a) +- d/(2a) = - 5/14 +- (25.87)/14 = (-5 +- 25.87)/14`