How do you factor #27w^3z-z^4w^6#?
1 Answer
Apr 7, 2017
Explanation:
The difference of cubes identity can be written:
#a^3-b^3 = (a-b)(a^2+ab+b^2)#
We will use this with
Given:
#27w^3z-z^4w^6#
First note that both of the terms are divisible by
#27w^3z-z^4w^6 = w^3z(27-z^3w^3)#
#color(white)(27w^3z-z^4w^6) = w^3z(3^3-(zw)^3)#
#color(white)(27w^3z-z^4w^6) = w^3z(3-zw)(3^2+3zw+(zw)^2)#
#color(white)(27w^3z-z^4w^6) = w^3z(3-zw)(9+3zw+z^2w^2)#
This is as far as we can go with Real coefficients.
The remaining quartic factor