Question #1fadf
1 Answer
Apr 7, 2017
Explanation:
The equation of a line in
#color(blue)"point-slope form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))#
where m represents the slope and# (x_1,y_1)" a point on the line"#
#"here "m=-4/3" and " (x_1,y_1)=(-6,2)#
#y-2=-4/3(x-(-6))#
#rArry-2=-4/3(x+6)larrcolor(red)" in point-slope form"# distribute and simplify gives an alternative version of the equation.
#y-2=-4/3x-8#
#rArry=-4/3x-8+2#
#rArry=-4/3x-6larrcolor(red)" in slope-intercept form"#