How do you multiply #(t^2+0.5)(t^2-0.5)#?

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Answer 1 · 2017-04-09T01:51:56

Use distributive property

#(t^2+0.5)(t^2−0.5)#

We have to multiply #(t^2+0.5)# into #(t^2−0.5)#

So, #t^2 * t^2# which is #t^4# as when you multiply powers with the same base you add the exponents. Then it is #t^2 * -0.5# which #−0.5t^2#

Then, #+0.5*t^2# which is #0.5t^2#. Next, #+0.5*-0.5# which is #-.25#

Therefore we have,

#t^4−0.5t^2+0.5t^2-0.25#

Now all we have to do is combine like terms and the final answer is #t^4−0.25#