A cylinder has inner and outer radii of $8 cm$ and $15 cm$ , respectively, and a mass of $1 kg$ . If the cylinder's frequency of counterclockwise rotation about its center changes from $15 Hz$ to $9 Hz$ , by how much does its angular momentum change?

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Answer 1 · 2017-04-09T08:06:43

The change in angular momentum is $=0.54kgm^2s^-1$

The angular momentum is $L=Iomega$

Mass, $m=1kg$

For a cylinder, $I=m((r_1^2+r_2^2))/2$

So, $I=1*((0.08^2+0.15^2))/2=0.0145kgm^2$

The change in angular momentum is

$DeltaL=IDelta omega$

The change in angular velocity is

$Delta omega=(15-9)*2pi=(12pi)rads^-1$

The change in angular momentum is

$DeltaL=0.0145*12pi=0.54kgm^2s^-1$

A cylinder has inner and outer radii of 8 cm8 cm and 15 cm15 cm, respectively, and a mass of 1 kg1 kg. If the cylinder's frequency of counterclockwise rotation about its center changes from 15 Hz15 Hz to 9 Hz9 Hz, by how much does its angular momentum change?